This is is no way to be taken as a RTFM type of reply. I really like the XML
entry in livedocs for this

http://livedocs.adobe.com/flex/3/langref/XML.html

Scroll down to the examples area.  A really great ref on using e4x.

Any one up for volunteering to speak to e4x use?

DK
Douglas Knudsen
http://www.cubicleman.com
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On Mon, Mar 30, 2009 at 11:34 AM, Atlanta Geek <[email protected]>wrote:

> Thanks guys. That was exactly the problem.
>
> On Sun, Mar 29, 2009 at 10:40 AM, Darin Kohles <[email protected]> wrote:
> > to be safe (assuming you don't nest)
> >
> > channels..channel[...@name
> >
> > its the '.@' that is missing in your code:
> >
> > you can also do...
> >
> > myXMLroot..(@name == "bob") ; // doesn't matter how nested the node with
> > "bob" as an attribute is.
> >
> > On Sun, Mar 29, 2009 at 8:16 AM, Justin Nichols <
> [email protected]>
> > wrote:
> >>
> >> See if this helps:
> >>
> >> var xml:XML =
> >>        <rootTag>
> >>                <channel name="a"/>
> >>                <channel name="b"/>
> >>                <channel name="c"/>
> >>        </rootTag>;
> >>
> >> var list:XMLList = xml.channel;
> >>
> >> var firstChannelName:String = list[...@name;  // may need to toString()
> or
> >> cast as String
> >>
> >> Thanks,
> >>
> >> Justin Nichols
> >>
> >>
> >> On Mar 29, 2009, at 8:08 AM, Atlanta Geek wrote:
> >>
> >>> So I have an XMLList  (named channels) that looks like this in xml
> >>>
> >>> <channel name="a"/>
> >>> <channel name="b"/>
> >>> <channel name="c"/>
> >>>
> >>> It is the data source for a combobox that is an item editor in a
> >>> datagrid.
> >>>
> >>> So how do I access the name attribute of the second channel.
> >>> channels[1].name  does not give me the name value. Any suggestions?
> >>>
> >>> --
> >>> http://www.atlantageek.com
> >>>
> >>>
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> >>
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> >
> >
> >
> > --
> > Darin Kohles
> > RIA Developer
> >
>
>
>
> --
> http://www.atlantageek.com
>
>
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