Howdy --
In python, conditionals only evaluate the appropriate branch and only
after evaluating the condition. We can say:
if 'foo' in bar_dict:
print bar_dict['foo']
else:
print "Foo not in bar"
Even if bar_dict doesn't have a key 'foo' the first branch of the
conditional is not evaluated, and so a KeyError is not raised. Every
language does this.
However Django's template system evaluates the branches prior to
determining which will be followed. The following template will raise
a TemplateSyntaxError:
{% ifequal 0 1 %}{% load non_existant_tag_library %}{% endifequal %}
... because non_existant_tag_library doesn't exist. This should not
raise a TemplateSyntaxError.
I've submitted a patch on ticket #7251 to correct this. Thanks!
-jag
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