Hello Django users and developers! I found that Django's function *model_to_dict()* is useful in some cases. For example, I can transform any Django ORM object to a Python's dict.
But the problem that I found - that I can't grab all Model fields, because *model_to_dict()* return only fields that *aren't hidden*. And I decided to add one extra argument to this function that allow us to get ALL fields, including hidden ones. I named this argument - include_hidden=True - but guys from Django core team found this naming as not well. Please help us to find the best name for this additional argument. Please find these two tickets - on djangoproject.com <https://code.djangoproject.com/ticket/25198> and on github.com <https://github.com/django/django/pull/5070> Thank you! Anton -- You received this message because you are subscribed to the Google Groups "Django developers (Contributions to Django itself)" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-developers+unsubscr...@googlegroups.com. To post to this group, send email to django-developers@googlegroups.com. Visit this group at http://groups.google.com/group/django-developers. To view this discussion on the web visit https://groups.google.com/d/msgid/django-developers/aa9e7693-f55e-4dea-ac56-dc31fd4ff4a7%40googlegroups.com. For more options, visit https://groups.google.com/d/optout.
