Hi Elton,

Django makes the Meta class of abstract models available as Foo.Meta. This 
allows you to define common Meta options on the abstract base class, and 
inherit the base Meta in your concrete child models. So the above example 
won't work as you noted, but this will:

class Foo(models.Model):
    class Meta:
        app_label = 'app'
        abstract = True

class Bar(models.Model):
    class Meta(Foo.Meta):

assert 'app_label' not in Bar.Meta.__dict__
assert Bar.Meta.app_label == 'app'

On Monday, January 18, 2016 at 6:34:29 PM UTC+1, Elton Pereira de Lima 
> Hello charettes!
> Analyzing the code further, I saw that it was impossible for the Bar Meta 
> class inherits from Foo.Meta because when this code 
> <https://github.com/django/django/blob/master/django/db/models/base.py#L108> 
> is executed, the Meta class ceases to exist because of this line 
> <https://github.com/django/django/blob/master/django/db/models/options.py#L212>
> .

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