#17415: django.contrib.sites.management.create_default_site populates invalid data in DB -------------------------------------+------------------------------------- Reporter: niko@… | Owner: nobody Type: Bug | Status: new Component: contrib.sites | Version: SVN Severity: Release blocker | Resolution: Keywords: site admin create | Triage Stage: db orm | Unreviewed Has patch: 0 | Needs documentation: 0 Needs tests: 0 | Patch needs improvement: 0 Easy pickings: 0 | UI/UX: 0 -------------------------------------+------------------------------------- Changes (by aaugustin):
* needs_better_patch: => 0 * type: Uncategorized => Bug * needs_tests: => 0 * needs_docs: => 0 Old description: > With a PostgeSQL backend, in trunk revision 1.4 pre-alpha SVN-17189 > > During syncdb, in the function > django.contrib.sites.management.create_default_site, > the default Site 'exemple.com' is created. > But for some reason, the postgres sequence 'django_site_id_seq' is then > in an incorrect state. > The last value = 1 (this is ok) > but the flag "Will increment last value before returning next value > (is_called)" = No > And this parameter is different in any other table generated by the ORM. > > Name Start value Last value Increment by Max value > Min value Cache value Log count Can cycle? Will > increment last value before returning next value (is_called)? > django_site_id_seq 1 1 1 9223372036854775807 1 > 1 1 No No > > What happens then? > If you go to the admin and want to add a second Site, when u save, you > get the exception: > > Exception Type: IntegrityError > > duplicate key value violates unique constraint "django_site_pkey" > DETAIL: Key (id)=(1) already exists. > > At this point, the add in the DB failed, but the ORM just changed the > flag in the Sequence django_site_id_seq.is_called = Yes > > This will allow the next attempt to save this second Site (reload the > page and resend the POST data, by exemple) to succeed. > > How to reproduce the bug at this stage: > in the postgresql, delete the table django_site, run manage.py syncdb, > this will create a new table and repopulate the exemple.com default Site, > and the buggy is_called tag on the django_site_id_seq sequence. > > Then, i dont know why the function > django.contrib.sites.management.create_default_site is putting this tag > to False. > > I havent tested on mysql, andi dont know how increment index is working > there. New description: With a PostgeSQL backend, in trunk revision 1.4 pre-alpha SVN-17189 During syncdb, in the function django.contrib.sites.management.create_default_site, the default Site 'exemple.com' is created. But for some reason, the postgres sequence 'django_site_id_seq' is then in an incorrect state. The last value = 1 (this is ok) but the flag "Will increment last value before returning next value (is_called)" = No And this parameter is different in any other table generated by the ORM. {{{ Name Start value Last value Increment by Max value Min value Cache value Log count Can cycle? Will increment last value before returning next value (is_called)? django_site_id_seq 1 1 1 9223372036854775807 1 1 1 No No }}} What happens then? If you go to the admin and want to add a second Site, when u save, you get the exception: {{{ Exception Type: IntegrityError duplicate key value violates unique constraint "django_site_pkey" DETAIL: Key (id)=(1) already exists. }}} At this point, the add in the DB failed, but the ORM just changed the flag in the Sequence django_site_id_seq.is_called = Yes This will allow the next attempt to save this second Site (reload the page and resend the POST data, by exemple) to succeed. How to reproduce the bug at this stage: in the postgresql, delete the table django_site, run manage.py syncdb, this will create a new table and repopulate the exemple.com default Site, and the buggy is_called tag on the django_site_id_seq sequence. Then, i dont know why the function django.contrib.sites.management.create_default_site is putting this tag to False. I havent tested on mysql, andi dont know how increment index is working there. -- -- Ticket URL: <https://code.djangoproject.com/ticket/17415#comment:1> Django <https://code.djangoproject.com/> The Web framework for perfectionists with deadlines. -- You received this message because you are subscribed to the Google Groups "Django updates" group. To post to this group, send email to django-updates@googlegroups.com. To unsubscribe from this group, send email to django-updates+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-updates?hl=en.