#19569: Add "widgets" argument to function's modelformset_factory inputs -----------------------------+-------------------- Reporter: Ameriks | Owner: nobody Type: New feature | Status: new Component: Forms | Version: 1.4 Severity: Normal | Keywords: Triage Stage: Unreviewed | Has patch: 1 Easy pickings: 1 | UI/UX: 0 -----------------------------+-------------------- Function modelformset_factory doesn't have widgets=None in it's input arguments, but function modelform_factory (which is called from def modelformset_factory) widgets is defined as optional input argument.
As the fix is in 2 lines, then I included it in the description. So the fix would be: {{{ def modelformset_factory(model, form=ModelForm, formfield_callback=None, formset=BaseModelFormSet, extra=1, can_delete=False, can_order=False, max_num=None, fields=None, exclude=None, widgets=None): """ Returns a FormSet class for the given Django model class. """ form = modelform_factory(model, form=form, fields=fields, exclude=exclude, formfield_callback=formfield_callback, widgets=widgets) FormSet = formset_factory(form, formset, extra=extra, max_num=max_num, can_order=can_order, can_delete=can_delete) FormSet.model = model return FormSet }}} -- Ticket URL: <https://code.djangoproject.com/ticket/19569> Django <https://code.djangoproject.com/> The Web framework for perfectionists with deadlines. -- You received this message because you are subscribed to the Google Groups "Django updates" group. To post to this group, send email to django-updates@googlegroups.com. To unsubscribe from this group, send email to django-updates+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.