Hi Bill,
On Thu, 2006-03-02 at 23:29 +0000, Bill de hÓra wrote:
>
> I'm trying to understand how dictionary lookups work in templates. To
> that end I'm passing in a dictionary of lists like this,
>
> allyears = {"2002":["a","b","c"], "2003":["a","b","c"]}
> return render_to_response('press/inthepress_index',
> "allyears":allyears,)
>
> into the template, ie in the webpage, show all thingies for each year.
>
> I have a corresponding fragment like this in a template:
>
> [[[
> {% for yearkey in allyears.keys %}
> <h3>{{yearkey}}</h3>
> <ul>
> {% for entry in allyears.yearkey %}
> <li>{{entry}}</li>
> {% endfor %}
> </ul>
> {% endfor %}
> ]]]
[...snip...]
So reorganising the data structure as nested lists has already been
suggested, but I suspect if you have dictionaries then you want to use
dictionaries (I would). Although there is no natural way to do what you
want, that I know of, here is one solution that works
{% for data in data.items %}
<h3>{{data.0}}</h3>
<ul>
{% for entry in data.1 %}
<li>{{entry}}</li>
{% endfor %}
</ul>
{% endfor %}
Just using the fact that you can refer to the list items by position:
data.0 and data.1 are converted to data[0] and data[1] in Python terms
and so iterate over the keys and values respectively.
Cheers,
Malcolm
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