On Fri, 2006-03-03 at 13:28 +1100, Malcolm Tredinnick wrote:
> Hi Bill,
>
> On Thu, 2006-03-02 at 23:29 +0000, Bill de hÓra wrote:
> >
> > I'm trying to understand how dictionary lookups work in templates. To
> > that end I'm passing in a dictionary of lists like this,
> >
> > allyears = {"2002":["a","b","c"], "2003":["a","b","c"]}
> > return render_to_response('press/inthepress_index',
> > "allyears":allyears,)
> >
> > into the template, ie in the webpage, show all thingies for each year.
> >
> > I have a corresponding fragment like this in a template:
> >
> > [[[
> > {% for yearkey in allyears.keys %}
> > <h3>{{yearkey}}</h3>
> > <ul>
> > {% for entry in allyears.yearkey %}
> > <li>{{entry}}</li>
> > {% endfor %}
> > </ul>
> > {% endfor %}
> > ]]]
> [...snip...]
>
> So reorganising the data structure as nested lists has already been
> suggested, but I suspect if you have dictionaries then you want to use
> dictionaries (I would). Although there is no natural way to do what you
> want, that I know of, here is one solution that works
>
> {% for data in data.items %}
Err.. I suck. This should be {% for data in allyears.items %}. :-(
> <h3>{{data.0}}</h3>
> <ul>
> {% for entry in data.1 %}
> <li>{{entry}}</li>
> {% endfor %}
> </ul>
> {% endfor %}
Malcolm
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