Hi: natebeacham: Yup, using item.category.name works fine =).
Using string interpolation on item.category also works - I was silly, forgot to restart the gunicorn process (I suppose you have to restart it after any changes to views.py, right? Or does it pick it up automatically after a while?). So between the two approaches, using item.category.name, and using string interpolation is one preferable to the other? Jikra: Thanks for the tip =). I did try Pisa for a bit, but for some reason, it was just timing out when I tried to integrate it into Django. The reason I didn't push harder to investigate the issue was that firstly, the command-line utility seemed to have pretty poor performance anyway. And secondly, Pisa itself seems to have been discontinued: http://groups.google.com/group/xhtml2pdf/browse_thread/thread/32dcee769245fc8f Finally, Pisa (and other approaches wkhtmltopdf) seem to require a lot more dependencies installed/setup - reportlab is just a single package to compile. But yeah, I'd still love if there was a separate template I could use to generate the PDF. It just feels very weird building up the PDF line by line in views.py. Cheers, Victor On Nov 18, 8:14 pm, Jirka Vejrazka <[email protected]> wrote: > Hi Victor, > > It really depends on complexity of your PDF. I needed to do > something similar some time ago and used ReportLab addon called "pisa" > and used standard Django template language to define the PDF contents. > > You might want to take a look, it worked well enough for simple PDF pages. > > Cheers > > Jirka > > On 18/11/2010, Victor Hooi <[email protected]> wrote: > > > > > > > > > Hi, > > > I'm trying to use ReportLab to produce a PDF output for one of my > > views. > > > My first question is - at the moment, I'm building up the PDF inside > > my view. Is this really the recommended way of doing it? It's like > > I've got presentation code inside my view (controller). Isn't there a > > cleaner way of doing it, or going from a template to PDF somehow? (I > > know ReportLab offers a commercial package using RML templates, > > however I was hoping for an opensource/free method). > > > Second question, I have a model with several FK fields. E.g. > > > class Article(models.Model): > > category = models.ForeignKey(Category) > > subject = models.ForeignKey(Subject) > > > Both the category and subject classes have fields called "name", and > > __unicode__ methods defined which return name. > > > I'm trying to refer to these fields in my PDF output. I have a list of > > items in article_list (i.e. queryset): > > > for item in article_list: > > text = item.category > > category = Paragraph(text, styles['Heading2']) > > story.append(category) > > > text = '%s' % item.subject > > subject = Paragraph(text, styles['Heading3']) > > story.append(subject) > > > When I try to run this code, I get: > > > 'Category' object has no attribute 'split' > > > and the same error with subject, obviously, once it gets to that bit > > of the code. > > > Any idea why this might be, or how to fix it? Any help is much > > appreciated. > > > Cheers, > > Victor > > > -- > > You received this message because you are subscribed to the Google Groups > > "Django users" group. > > To post to this group, send email to [email protected]. > > To unsubscribe from this group, send email to > > [email protected]. > > For more options, visit this group at > >http://groups.google.com/group/django-users?hl=en. -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
