You mean like this:
var data = {
url: item.find("#id_url").val(),
title: item.find("#id_title").val(),
tags: item.find("#id_tags").val(),
share: item.find("#id_share").val()
};
Tried it. 'share' is still showing up false...
On Jul 21, 1:29 am, Daniel Roseman <[email protected]> wrote:
> On Thursday, July 21, 2011 4:00:55 AM UTC+1, ed wrote:
>
> > I'm using the following javascript, so I can't check the HTML, can I?
> > How would I go about debugging this?
>
> > function bookmark_save() {
> > var item = $(this).parent();
> > var data = {
> > url: item.find("#id_url").val(),
> > title: item.find("#id_title").val(),
> > tags: item.find("#id_tags").val()
> > };
> > $.post("/save/?ajax", data, function (result) {
> > if (result != "failure") {
> > item.before($("li", result).get(0));
> > item.remove();
> > $("ul.bookmarks .edit").click(bookmark_edit);
> > }
> > else {
> > alert("Failed to validate bookmark before saving.");
> > }
> > });
> > return false;
> > }
>
> > function bookmark_edit() {
> > var item = $(this).parent();
> > var url = item.find(".title").attr("href");
> > item.load(
> > "/save/?ajax&url=" + encodeURIComponent(url),
> > null,
> > function () {
> > $("#save-form").submit(bookmark_save);
> > }
> > );
> > return false;
> > }
>
> > $(document).ready(function () {
> > $("ul.bookmarks .edit").click(bookmark_edit);
> > });
>
> But surely the problem is that you haven't supplied a value for `share` in
> your Ajax data.
> --
> DR.
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