Hello,
I have an issue, I am creating a website that will be available in many
languages, sharing the same database.
Most models have a "language" attribute that is the 2 letters from the
language code (en, es, fr, etc.).
I am trying to find a way to show the correct content per language.
I tried many things, creating a custom manager :
from django.utils.translation import get_language, get_language_info
from django.db import models
class PerLanguageManager(models.Manager):
def get_queryset(self):
if get_language():
return super(PerLanguageManager, self).get_queryset().filter(
language=get_language_info(get_language())['code'])
else:
return super(PerLanguageManager, self).get_queryset()
Or overriding get_queryset using another method : (The language is always
present in the url as /en/ or /es/)
class RecipeIndexView(generic.ListView):
paginate_by = 10
def get_queryset(self):
return
Recipe.objects.filter(language=get_language_from_request(self.request,
check_path=False))
But nothing work, I always get the default configured language (even if
with the debug toolbar tell me the site is in another language, and all the
translations are correctly done in the language specified in the URL, I
always get the default language from the queries...)
I'm using a specific middleware to ignore the language specified in the
browser to only use the language specified in the URL :
class ForceDefaultLanguageMiddleware(object):
"""
Ignore Accept-Language HTTP headers
This will force the I18N machinery to always choose
settings.LANGUAGE_CODE
as the default initial language, unless another one is set via sessions
or cookies
Should be installed *before* any middleware that checks
request.META['HTTP_ACCEPT_LANGUAGE'],
namely django.middleware.locale.LocaleMiddleware
"""
def process_request(self, request):
if 'HTTP_ACCEPT_LANGUAGE' in request.META:
del request.META['HTTP_ACCEPT_LANGUAGE']
Any idea of how to make this work ? What is the good way to do this ?
Thank you.
Mathieu
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