Thanks for the reply.Well i used the same model shown in the
documentation.I even cross checked all my codes to verify that anything is
out of place.Even then the error appears.
On Thursday, June 15, 2017 at 11:12:55 PM UTC+5:30, Hemhem wrote:
>
> TypeError: 'choice_text' is an invalid keyword argument for this function
> That above, is where the problem is where the problem is so I am going to
> guess you need to check your model if you wrote everything correctly.
> If I can see what your model looks like, I can probe in.
>
> On Thu, Jun 15, 2017 at 10:34 AM, danbmathew <danbm...@gmail.com
> <javascript:>> wrote:
>
>> Well I'm new to django and my code is just as in the documentation.But
>> got an error while trying to run the codeline q.choice_set.create(
>> choice_text='Not much', votes=0).
>> This part of the code is almost at the end of the segment named Playing
>> With API.I will also post the error.
>>
>> Traceback (most recent call last):
>> File "<console>", line 1, in <module>
>> File
>> "C:\Users\DELL\AppData\Local\Programs\Python\Python36-32\lib\site-packages\django\db\models\fields\related_descriptors.py",
>>
>> line 653, in create
>> return super(RelatedManager, self.db_manager(db)).create(**kwargs)
>> File
>> "C:\Users\DELL\AppData\Local\Programs\Python\Python36-32\lib\site-packages\django\db\models\manager.py",
>>
>> line 85, in manager_method
>> return getattr(self.get_queryset(), name)(*args, **kwargs)
>> File
>> "C:\Users\DELL\AppData\Local\Programs\Python\Python36-32\lib\site-packages\django\db\models\query.py",
>>
>> line 392, in create
>> obj = self.model(**kwargs)
>> File
>> "C:\Users\DELL\AppData\Local\Programs\Python\Python36-32\lib\site-packages\django\db\models\base.py",
>>
>> line 571, in __init__
>> raise TypeError("'%s' is an invalid keyword argument for this
>> function" % list(kwargs)[0])
>> TypeError: 'choice_text' is an invalid keyword argument for this function
>>
>>
>> Please help me.
>>
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>
>
>
> --
> Elegbede Muhammed Oladipupo
>
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