well umm. can I add urls though the admin interface?
On 28 May 2008, at 19:42, Eric Abrahamsen wrote:

>
> What I was originally suggesting you do (which of course might not
> turn out to be the best solution) is use feedparser to read feed urls,
> and save those feeds into your database. That way, you wouldn't be
> using feedparser at all in your views, just regular database queries.
>
> If your models include Feed and FeedItem (FeedItem having a foreignkey
> to a Feed), then feed parser will do something like this:
>
> f = feedparser.parse('http://somefeed.url')
> feed = Feed.objects.get(link=f.feed.link) # f.feed provides
> information corresponding to one Feed instance
> for item in f['entries']: # entries are all the items under a
> particular feed
>      it, created = FeedItem.objects.get_or_create(title=item.title,
> link=item.link, desc=item.description, date=item.date_parsed,
> id=item.id, feed=feed)
>
> Repeat the above for every url in your list of feed urls. Note: this
> code goes in your standalone script running on a cron job, NOT in your
> views or whatever other normal part of your django code base. That
> will put RSS feed items into your database, your views.py pulls them
> out again as per normal django methods:
>
> feed = Feed.objects.get(link=somelinkvalue)
> items = feed.feeditem_set.all()
> return render_to_response(template, {'items':items})
>
> That's how it ought it work, in my opinion. Note that it's late here,
> and I've been drinking, so there may be some inaccuracies in the
> above. I concur with the general consensus, that you need to start
> with some simple CGI scripts and python basics, and move up from
> there. That said, good luck!
>
> E
>
>
> On May 28, 2008, at 11:45 PM, sebey wrote:
>
>>
>> please much suggestions thank you
>>
>> On May 28, 4:37 pm, sebastian stephenson <[EMAIL PROTECTED]> wrote:
>>> great finally some help thank you so much!
>>> On 28 May 2008, at 15:20, Rajesh Dhawan wrote:
>>>
>>>
>>>
>>>
>>>
>>>> On May 28, 6:30 am, sebey <[EMAIL PROTECTED]> wrote:
>>>>> from django.http import HttpResponse
>>>>> import feedparser
>>>>> from ubermicro.shows.models import show
>>>
>>>>> def show_page(request):
>>>>>    """this is where we take what we need form the rss feeds in the
>>>>> data base"""
>>>>>    query = show.objects.filter(show_feed__contains="http://";)
>>>>>    podcast = feedparser.parse(query)
>>>
>>>> It seems that you are making feedparser parse an instance of a
>>>> Django
>>>> ORM query. I think what you want to do is to make it parse a URL.
>>>> May
>>>> be something like this:
>>>
>>>> for q in query:
>>>>    podcast = feedparser.parse(q.show_feed)
>>>>    if podcast.entries:
>>>>       show_latest_title = podcast.entries[0].title
>>>
>>>> This will do it for all objects in your query. So you will have to
>>>> collect that list of titles etc. in a collection of some kind  
>>>> (list,
>>>> dict, etc.) and pass it on to your template.
>>>
>>>>>    #show_about = podcast.feed.description
>>>>>    show_latest_title = podcast.entries[0].title
>>>
>>>> The above statement assumes that there is at least one entry in the
>>>> feed. That may not be always true. So, you should consider testing
>>>> that first. Something like:
>>>
>>>> if podcast.entries:
>>>>  show_latest_title = podcast.entries[0].title
>>>
>>>>>    #show_latest = podcast.entries[0].description
>>>
>>>>>    return  HttpResponse(show_latest_title)
>>>
>>>>> this code is what I think its doing is that I am grabing the rss
>>>>> url
>>>>> then using feedparser (http://www.feedparser.org) to get rss
>>>>> element
>>>>> such as <description> and such but every time I try to do this I
>>>>> get
>>>>> this error
>>>
>>>>> Traceback (most recent call last):
>>>>> File "/Library/Frameworks/Python.framework/Versions/2.5/lib/
>>>>> python2.5/
>>>>> site-packages/django/core/handlers/base.py" in get_response
>>>>>  77. response = callback(request, *callback_args,
>>>>> **callback_kwargs)
>>>>> File "/Users/sebey/Sites/ubermicro/../ubermicro/shows/views.py" in
>>>>> show_page
>>>>>  10. show_latest_title = podcast.entries[0].title
>>>
>>>>>  IndexError at /shows/
>>>>>  list index out of range
>>>>> I am to django programing web dev etc. but I guess that the query
>>>>> I am
>>>>> useing is not correct so I what should I do thanks
>>>
>>>> -Rajesh
>>>
>>> see ya
>>>
>>> sebey
>>>
>
>
> >

see ya

sebey



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