If you convert timea into a normal datetime instance just substract timea from timeb and you will get a datetime.timedelta instance which has everything you need :-)
import datetime a = datetime.datetime(2008, 11, 15) b = datetime.datetime.now() print b-a -- Horst On Fri, Nov 28, 2008 at 7:24 PM, Bobby Roberts <[EMAIL PROTECTED]> wrote: > I need to know the # of seconds between two dates for my django > application. I believe this has to be done with straight python. > I've read the py docs on time functions but it doesn't make sense to > me. Can anyone help? Here's my situation: > > timea='11/15/2008 11:35 AM' > > timeb=datetime.now() > > How can I calculate the diff between timeb and timea in seconds? > > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---