Please take a look at the documentation for the datetime and time modules :-)
>>> import datetime
>>> datetime.datetime.strptime('2008-09-16 08:01:16', '%Y-%m-%d %H:%M:%S')
-- Horst
On Fri, Nov 28, 2008 at 10:13 PM, Bobby Roberts <[EMAIL PROTECTED]> wrote:
> On Nov 28, 1:35 pm, "Horst Gutmann" <[EMAIL PROTECTED]> wrote:
>> If you convert timea into a normal datetime instance just substract
>> timea from timeb and you will get a datetime.timedelta instance which
>> has everything you need :-)
>>
>> import datetime
>> a = datetime.datetime(2008, 11, 15)
>> b = datetime.datetime.now()
>>
>> print b-a
>>
>> -- Horst
>
>
>
> Well I need to know the exact # of seconds from 2008-09-16 08:01:16
> to now.... not from just a date to date. It has to be exact... does
> this make sense. I was looking at this page
> http://pleac.sourceforge.net/pleac_python/datesandtimes.html in the
> "Converting DMYHMS to Epoch Seconds" section. I thought perhaps it
> would be easier to just get the epoch seconds between this time, and
> NOW() and subtract the two, however I keep getting an error locally in
> my terminal window reading:
>
>>>> import time
>>>> import datetime
>>>> t=datetime.datetime('2008-09-16 08:01:16')
>
> Traceback (most recent call last):
> File "<stdin>", line 1, in <module>
> TypeError: function takes at least 3 arguments (1 given)
>
>
>
> >
>
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