> <snip> > > The question, how can I return username of user in fields. I want > the JSON response to contain value user.username instead of id of > user oject > > Thanks, > Oleg >
Get everything you want into a dictionary. Then something like this will give you what you need: return safestring.mark_safe(simplejson.dumps(return_vals)) If you want to return JSON to an AJAX call, then this will work: return HttpResponse(your_json_object, mimetype="application/json") --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
