On Sat, Jan 23, 2016 at 04:45:05PM +0100, Didier Kryn wrote: > Le 23/01/2016 12:16, Didier Kryn a écrit : > > > > I'm curious of the reason why you specify > > static void print_start(char const *name, char const *what) > > > > This means the pointers to the arrays of characters are > >constant (not the characters). The effect of this cannot be to > >protect the pointers in the caller program since they are passed > >by value -- copied into register or stack before passing control > >to the function. If it is for the sanity of the function itself, > >then congratulations, this is a sane thing to do, even if it is > >easy to check by eye that the pointers aren't modified. But, to be > >consistent, since your function doesn't even modify the content of > >the strings, you should also declare constant the characters > >themself, like in the following: > > static void print_start(const char const *name, const char > >const *what) > > Sorry, I overlooked the code and read "char const *name" as if > it was "char * const name". Actually the syntax you used is > equivalent to "const char *name". It actually protects the string > from being overwritten by the function.
I've always said the C syntax for declarators was confusing. Even those who understand it read it wrong! (Yes, In understand the logic behind it. It is still confusing.) -- hendrik _______________________________________________ Dng mailing list Dng@lists.dyne.org https://mailinglists.dyne.org/cgi-bin/mailman/listinfo/dng
