You could try something like this. Note: the context of the sorting
XPath is the XPath's result.
try {
SAXReader reader = new SAXReader();
Document document = reader.read( "file:sort.xml");
XPath xpath = DocumentHelper.createXPath("//item");
XPath sortXPath = DocumentHelper.createXPath("@name");
List nodes = xpath.selectNodes(document, sortXPath);
for ( int i = 0; i < nodes.size(); i++) {
System.out.println( ((Node)nodes.get(i)).asXML());
}
} catch ( DocumentException e) {
// the document is not well-formed.
e.printStackTrace();
}
The XML used was the following:
<items>
<item name="bbb"/>
<item name="ccc"/>
<item name="aaa"/>
</items>
Regards,
Edwin
--
http://www.edankert.com/
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