I had assumed that he had created the window on one thread and then called Show on a different one.
In that case it wouldn't work, it's definitely wrong, but you also don't get an exception. This is an instance of a more general problem: although it's positively forbidden to use a Control from the wrong thread, you never actually get any indication from the runtime when you've done it wrong. There is no WrongThreadException. This is disappointing, as it means that people learning Windows Forms make this mistake time and again because there are no obvious symptoms that something is wrong. It would be great if controls actually checked the calling thread ID. But we have been told in the past on this list that this was considered to be too expensive, and unfair on the code that actually gets it right... However, if I misunderstood what was being said in *this* discussion, and *everything* was being done on the worker thread, then that's a slightly different problem. In that case, this is not the classic failure to call Control.Invoke, this is a slightly different error. As you say, it sounds like an 'message pumps on a thread pool thread are not a good idea' thing. So I think we need to refer back to the original poster. Jeff, what exactly are you doing? Are you creating a form object on the timer thread? Or was the form created elsewhere, and you are just trying to call Show from the timer thread? (In any case the solution will be the same: don't do UI stuff on a worker thread - you don't own the worker thread. Which means either don't use the System.Timers.Timer class, or if you must, use Control.Invoke to get the real work done on the right thread.) -- Ian Griffiths DevelopMentor ----- Original Message ----- From: "Matthew Adams" <[EMAIL PROTECTED]> > How would the Form know that it needed to throw an exception? As I said, > there is nothing intrinsically wrong with creating the Form and calling > Show() from the Timer thread. The 'no-return' behaviour you get is, I > guess, because a message pump is started when you create the first > window on a thread, and so it never comes back, not because it is a > thread pool thread. > > So, essentially, it is all behaving correctly. Why would there be an > exception? > > Matthew > > -----Original Message----- > From: Jeff Roberts > > It sure would have saved me a lot of time if an exception had been > thrown ! You can read messages from the DOTNET archive, unsubscribe from DOTNET, or subscribe to other DevelopMentor lists at http://discuss.develop.com.
