Hey dboy, "this" is NOT equal to "My" but it is equal to "Me", "My" is
actually a namespace introduced from VB 2005
On Fri, Sep 26, 2008 at 12:37 AM, dboy haha <[EMAIL PROTECTED]>wrote:
> To piggy back off of what sallushan said, We would like to see what the
> particular error is so we would know where to look, and "this" is the
> keyword that has the same functionality as "My" in C#. Sara using the "try",
> "catch", and "finally" statement to trap any exception when opening a file
> or a connection because if sometihing goes wrong and the program throws an
> exception you can potentially run out of file handles or leave a database
> connection open which is a security risk. Place exceptions within these
> statements.
>
> On Thu, Sep 25, 2008 at 3:10 PM, sallushan <[EMAIL PROTECTED]> wrote:
>
>>
>> You haven't mentioned, what and where the exception is occuring? I
>> don't know whether you are doing is the only way in C# or NOT, but we
>> have a very simple thing in Visual Basic i.e. "My". You can use it in
>> C# too. Add a reference to Microsoft.VisualBasic, then use the
>> following code to upload file,
>>
>> Microsoft.VisualBasic.Devices.Network n;
>> n = new Microsoft.VisualBasic.Devices.Network();
>> n.UploadFile("C:\\TestFile.txt", "ftp://www.mydomain.com/
>> testfile.txt", "userid", "password", true, 100);
>>
>> where,
>> true = display UI (progress) while uploading the file
>> 100 = connection timeout in milliseconds
>>
>> Above 3 lines will (inshaALLAH) upload the file with a UI displaying
>> the progress of uploading!
>>
>>
>> On Sep 25, 3:26 pm, sara <[EMAIL PROTECTED]> wrote:
>> > Hi,
>> >
>> > i am developing the tool that i want to transfer the file
>> > from local to remote. when i run the aplicatioon it shows some error.
>> > the below code i m using..
>> >
>> > //string filename = "c:\\test.xls";
>> > FileInfo fileInf = new FileInfo("c:\\test.xls");
>> > string uri = "ftp://"; + "Ipaddress" + "/" + fileInf.Name;
>> > FtpWebRequest reqFTP = (FtpWebRequest)
>> > FtpWebRequest.Create(uri);
>> > //HttpWebRequest reqFTP = (HttpWebRequest)
>> > HttpWebRequest.Create(uri);
>> >
>> > reqFTP.Credentials = new NetworkCredential("username",
>> > "password","domain");
>> > reqFTP.KeepAlive = false;
>> > reqFTP.Proxy = null;
>> >
>> > reqFTP.Method = WebRequestMethods.Ftp.UploadFile;
>> > //reqFTP.Method = WebRequestMethods.Http.Post;
>> > //reqFTP.uUseBinary = true;
>> > reqFTP.ContentLength = fileInf.Length;
>> >
>> > int buffLength = 2048;
>> > byte[] buff = new byte[buffLength];
>> > int contentLen;
>> > FileStream fs = fileInf.OpenRead();
>> >
>> > // Stream to which the file to be upload is written
>> > Stream strm = reqFTP.GetRequestStream();
>> >
>> > // Read from the file stream 2kb at a time
>> > contentLen = fs.Read(buff, 0, buffLength);
>> >
>> > // Till Stream content ends
>> > while (contentLen != 0)
>> > {
>> > // Write Content from the file stream to the FTP
>> > Upload
>> > // Stream
>> > strm.Write(buff, 0, contentLen);
>> > contentLen = fs.Read(buff, 0, buffLength);
>> > }
>> >
>> > // Close the file stream and the Request Stream
>> > strm.Close();
>> > fs.Close();
>> >
>> > please any one can help me to finish this task
>>
>>
>
> >
>
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