Thanks for the correction

On Sat, Sep 27, 2008 at 1:28 AM, Arsalan Tamiz <[EMAIL PROTECTED]> wrote:

> Hey dboy, "this" is NOT equal to "My" but it is equal to "Me", "My" is
> actually a namespace introduced from VB 2005
>
> On Fri, Sep 26, 2008 at 12:37 AM, dboy haha <[EMAIL PROTECTED]>wrote:
>
>> To piggy back off of what sallushan said, We would like to see what the
>> particular error is so we would know where to look, and "this" is the
>> keyword that has the same functionality as "My" in C#. Sara using the "try",
>> "catch", and "finally" statement to trap any exception when opening a file
>> or a connection because if sometihing goes wrong and the program throws an
>> exception you can potentially run out of file handles or leave a database
>> connection open which is a security risk. Place exceptions within these
>> statements.
>>
>> On Thu, Sep 25, 2008 at 3:10 PM, sallushan <[EMAIL PROTECTED]> wrote:
>>
>>>
>>> You haven't mentioned, what and where the exception is occuring? I
>>> don't know whether you are doing is the only way in C# or NOT, but we
>>> have a very simple thing in Visual Basic i.e. "My". You can use it in
>>> C# too. Add a reference to Microsoft.VisualBasic, then use the
>>> following code to upload file,
>>>
>>> Microsoft.VisualBasic.Devices.Network n;
>>> n = new Microsoft.VisualBasic.Devices.Network();
>>> n.UploadFile("C:\\TestFile.txt", "ftp://www.mydomain.com/
>>> testfile.txt", "userid", "password", true, 100);
>>>
>>> where,
>>> true = display UI (progress) while uploading the file
>>> 100 = connection timeout in milliseconds
>>>
>>> Above 3 lines will (inshaALLAH) upload the file with a UI displaying
>>> the progress of uploading!
>>>
>>>
>>> On Sep 25, 3:26 pm, sara <[EMAIL PROTECTED]> wrote:
>>> > Hi,
>>> >
>>> >          i am developing the tool that i want to transfer the file
>>> > from local to remote. when i run the aplicatioon it shows some error.
>>> > the below code i m using..
>>> >
>>> >  //string filename = "c:\\test.xls";
>>> >             FileInfo fileInf = new FileInfo("c:\\test.xls");
>>> >             string uri = "ftp://"; + "Ipaddress" + "/" + fileInf.Name;
>>> >             FtpWebRequest reqFTP = (FtpWebRequest)
>>> > FtpWebRequest.Create(uri);
>>> >             //HttpWebRequest reqFTP = (HttpWebRequest)
>>> > HttpWebRequest.Create(uri);
>>> >
>>> >             reqFTP.Credentials = new NetworkCredential("username",
>>> > "password","domain");
>>> >             reqFTP.KeepAlive = false;
>>> >             reqFTP.Proxy = null;
>>> >
>>> >             reqFTP.Method = WebRequestMethods.Ftp.UploadFile;
>>> >             //reqFTP.Method =  WebRequestMethods.Http.Post;
>>> >             //reqFTP.uUseBinary = true;
>>> >             reqFTP.ContentLength = fileInf.Length;
>>> >
>>> >             int buffLength = 2048;
>>> >             byte[] buff = new byte[buffLength];
>>> >             int contentLen;
>>> >             FileStream fs = fileInf.OpenRead();
>>> >
>>> >                 // Stream to which the file to be upload is written
>>> >                 Stream strm = reqFTP.GetRequestStream();
>>> >
>>> >                 // Read from the file stream 2kb at a time
>>> >                 contentLen = fs.Read(buff, 0, buffLength);
>>> >
>>> >                 // Till Stream content ends
>>> >                 while (contentLen != 0)
>>> >                 {
>>> >                     // Write Content from the file stream to the FTP
>>> > Upload
>>> >                     // Stream
>>> >                     strm.Write(buff, 0, contentLen);
>>> >                     contentLen = fs.Read(buff, 0, buffLength);
>>> >                 }
>>> >
>>> >                 // Close the file stream and the Request Stream
>>> >                 strm.Close();
>>> >                 fs.Close();
>>> >
>>> > please any one can help me to finish this task
>>>
>>>
>>
>>
>>
>
> >
>

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