On Mon, 30 Apr 2001 20:25:36 -0700, James H. Steiger <not@my_address>
wrote:
>If you read my post carefully, (assuming it made
>your server), you will see that
>it, indeed, gives the combinations solution you gave
>below, and shows that it is equivalent to
>another, more elegant way of arriving at the same
>answer, i.e.,
>
>2^N = (in this case) 2^5 = 32
>
>
It's amazing how much effort y'all put into doing some lazy pricks
homework for him
Gary Carson
http://www.garycarson.com
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