Bob, is this not isomorphic to a chi-square goodness of fit test?
For each coin, if you know or can estimate (separately from these 
data!) the probability of heads, you can calculate an expected number 
of heads from the number of times the coin is flipped.  You have an 
observed number of heads for that coin.  Sum ((O-E)^2)/E) for a chi-sq 
with (presumably) 99 d.f.
        The low _observed_ frequencies you mention are not a problem; 
the problem that occasions the usual caution has to do with a low (e.g., 
fractional) expected frequency coupled with a positive observed 
frequency, which can unreasonably inflate the total chi-sq.  (If the 
observed frequency is 0, the contribution of that coin to the total 
chi-sq. is merely the expected frequency.)  To some degree, should the 
problem arise (i.e., should there be largeish contributions to chi-sq. 
from a few cells because of observed frequencies of 2 and expected 
frequencies of, say, 0.05 [close to your worst case] and consequent 
contributions of 76 to the total chi-sq), you can reduce the intensity 
of the problem by combining categories;  although before doing that I 
would always want to look at the large contributors to see whether 
there may be something interesting going on.  One out of a hundred 
coins showing this behavior I'm prepared to ignore;  four or five 
doing so would excite my suspicion.
                                        -- DFB.

On Thu, 30 Mar 2000, Bob Parks wrote:

> Consider the following problem (which has a real world
> problem behind it)
> 
> You have 100 coins, each of which has a different
> probability of heads (assume that you know that
> probability or worse can estimate it).
> 
> Each coin is labeled.  You ask one person (or machine
> if you will) to flip each coin a different number of times,
> and you record the number of heads.
> 
> Assume that the (known/estimated) probability of heads
> is between .01 and .20, and the number of flips for
> each coin is between 4 and 40.
> 
> The question is how to test that the person/machine
> doing the flipping is flipping 'randomly/fairly'.  That is,
> the person/machine might not flip 'randomly/fairly/...'
> and you want to test that hypothesis.
> 
> One can easily state the null hypothesis as
> 
>   p_hat_i = p_know_i  for i=1 to 100
> 
> where p_hat_i is the observed # heads / # flips for each i.
> 
> Since each coin has a different probability of heads,
> you can not directly aggregate.
> 
> Since the expected number of heads is low, asymptotics for
> chi-squares will not apply (each coin has substantial
> probability of obtaining 0 heads so empirically you obtain
> lots of cells with 0,1,2 etc.).
> 
> Given that, I have failed to come up with a statistic to test it.
> 
> TIA for any pointers to help.
> 
> Bob

 ------------------------------------------------------------------------
 Donald F. Burrill                                 [EMAIL PROTECTED]
 348 Hyde Hall, Plymouth State College,          [EMAIL PROTECTED]
 MSC #29, Plymouth, NH 03264                                 603-535-2597
 184 Nashua Road, Bedford, NH 03110                          603-471-7128  



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