In article <[EMAIL PROTECTED]>, [EMAIL PROTECTED] says...
>
>We use multiple linear regression to perform our analyses. Because we
>work with binned data (discharge frequency of a neuron) which follow a
>non-normal (Poisson) distribution, we typically use the square root
>transform on the dependent variable (discharge rate of the neuron).
>(Actually, the transformation is sqrt(spike rate + 3/8) )
>
>I've been trying to show that some independent variables account for
>more of the variance explained in the dependent variable. However, some
>researchers in my field argue that the square root transform could
>artificially bias my results so that some independent variable account
>for more of the variance than they really should. I don't see how this
>could be from a theoretical level. Plus, I've run the multiple
>regression without the transform and seen only about a 5% difference
>(not much).
>
>Does anybody know if these criticisms have any theoretical merit? I
>can't see how this can be so. I thought that the square-root transform
>was a pretty sound way of reducing your chance of biasing the analysis
>if the data is non-normal (which most parametric tests require).
>
>Thanks.
>-Tony
>
>
>--
>///////////////////////////////////////////////////
>// G. Anthony Reina, MD //
>// The Neurosciences Institute //
>// 10640 John Jay Hopkins Drive //
>// San Diego, CA 92121 //
>// Phone: (858) 626-2132 //
>// FAX: (858) 626-2199 //
>////////////////////////////////////////////
You can try a straight Poisson regression. If the conclusions you obtained
from a Poisson regression are consistent with those from a square-root
transformation, you'd be OK. The main purpose of a square-root transform in
your case is to stabilize the variance of the error terms.
--
T.S. Lim
[EMAIL PROTECTED]
www.Recursive-Partitioning.com
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