mike anderson wrote in message ... >x is chi square with 2m d.o.f. what is the correlation between x and lnx? >thanks > >-- >Mike >
Continuing from my previous response, I find that the correlation is: 1/sqrt[m.zeta(2,m)] That looks nice and simple, doesn't it? - until you start looking for Riemann's zeta function, or what some authors call the generalized zeta function (it has 2 arguments). Now zeta(2,m) = sum of squares of reciprocals of m, m+1, m+2, m+3, ... This sum converges but painfully slowly. However, it is known that zeta(2,1) = pi^2 / 6 = 1.644934067.. Hence for small m, you can just subtract 1, 1/4, 1/9, 1/16, ... 1/(m-1)^2 from this. Finally this gives the numerical values which Colin Rose gave about 2 days ago! Cheers -- Alan Miller (Honorary Research Fellow, CSIRO Mathematical & Information Sciences) http://www.ozemail.com.au/~milleraj http://users.bigpond.net.au/amiller/ . . ================================================================= Instructions for joining and leaving this list, remarks about the problem of INAPPROPRIATE MESSAGES, and archives are available at: . http://jse.stat.ncsu.edu/ . =================================================================
