In article <a9knv2$807$[EMAIL PROTECTED]>, mike anderson <[EMAIL PROTECTED]> wrote: >x is chi square with 2m d.o.f. what is the correlation between x and lnx? >thanks
If X has a Gamma distribution with shape parameter t (t = m in your example) and scale factor s (2 in your example, but it does not affect the correlation, then V(X) = s^2*m; V(ln(X)) = \Psi'(m); Cov(X, ln(X)) = s, so the correlation is 1/sqrt(m*\Psi'(m)). -- This address is for information only. I do not claim that these views are those of the Statistics Department or of Purdue University. Herman Rubin, Dept. of Statistics, Purdue Univ., West Lafayette IN47907-1399 [EMAIL PROTECTED] Phone: (765)494-6054 FAX: (765)494-0558 . . ================================================================= Instructions for joining and leaving this list, remarks about the problem of INAPPROPRIATE MESSAGES, and archives are available at: . http://jse.stat.ncsu.edu/ . =================================================================
