The answer can be found in the "Encyclopedia of Integer Sequences", 
under the heading of "round-robin" tournaments.

http://www.research.att.com/cgi-bin/access.cgi/as/njas/sequences/eisA.cgi?Anum=A000571

I have reasonable confidence in this since the sequence matches my 
enumerations up to n = 7.

Neil Henry



Neil W. Henry wrote:
> Josh wrote:
> 
> 
>> If this is the case then we can apply a little graph theory to the
>> problem. Each boat is a vertex/node/point of the graph and each race
>> is represented by an edge/line/connection between each of the points.
>> Each edge is directed, i.e. it points from, say, vertex A to B and not
>> from B to A. Suppose that an edge directed from A to B means that boat
>> A beat boat B in a race. Since each boat races every other boat in the
>> group, there must be an edge connecting each pair of vertices. This is
>> called a tournament graph (not a surprising name, eh?).
>>
>> This graph is explained in Eric's world of mathematics
>>
>> http://mathworld.wolfram.com/Tournament.html
>>
>> and the sequence of distinct graphs is given by
>>
>> 
>http://www.research.att.com/cgi-bin/access.cgi/as/njas/sequences/eisA.cgi?Anum=000568 
>>
>>
>> Since there are only 9 syndicates in the Louis Vuitton Cup, the
>> sequence given in the previous web page should answer your question.
>> There also some references given if you want to find an extended
>> sequence
>>
>> I hope this helps!
>>
>> Regards,
>>
>>
>> Josh
> 
> 
> While your description of the graph is correct, the results given in 
> Harary and Palmer, and on the att webpage you cite, are not solutions to 
> this particular problem. In other words, there is a theorem that says 
> for n = 5 there are exactly 12 "tournaments" of a certain type, but this 
> is not the number of possible standings asked for.
> 
> My enumeration for n = 5 yields 9 possible standings (below). If I have 
> omitted one (or three!) please let me know.
> 
> Neil Henry, Virginia Commonwealth University
> 
> Standings for n = 5 round-robin competition:
>      4 3 2 1 0
>      4 3 1 1 1
>      4 2 2 2 0
>      4 2 2 2 1
>      3 3 3 1 0
>      3 3 2 2 0
>      3 3 2 1 1
>      3 2 2 2 1
>      2 2 2 2 2
> 

.
.
=================================================================
Instructions for joining and leaving this list, remarks about the
problem of INAPPROPRIATE MESSAGES, and archives are available at:
.                  http://jse.stat.ncsu.edu/                    .
=================================================================

Reply via email to