Hi, I have a question about Exception catching in EJB. How can I throw a
custom Exception from my EJB?
I created an Exception class that extends the java.lang.Exception and used
it inside the EJB to throw Exception
When I call my EJB from a bean requested from JSP file I get this error in
the srv.log file,
Feb 21 16:52:45 2001: SM
Feb 21 16:52:45 2001: at
com.dcsoft.isppro.ServerManagerBean.vsAddServer(ServerManagerBean.java:152)
Feb 21 16:52:45 2001: at
com.dcsoft.isppro._sk_DCSoft_ISPPro_ServerManager.invoke(_sk_DCSoft_ISPPro_S
erverManager.java:166)
Feb 21 16:52:45 2001: at com.sybase.CORBA.local.Socket.call(Native Method)
Feb 21 16:52:45 2001: at
com.sybase.CORBA.local.OutputStream.write(OutputStream.java:29)
Feb 21 16:52:45 2001: at
com.sybase.CORBA.iiop.Connection.invoke(Connection.java:1947)
Feb 21 16:52:45 2001: at
com.dcsoft.isppro.ServerManager_Stub.vsAddServer(ServerManager_Stub.java:44)
Feb 21 16:52:45 2001: at
com.dcsoft.isppro.ServerManagerLoader.vsAddServer(ServerManagerLoader.java:9
6)
Feb 21 16:52:45 2001: at
_0005cAddServerPrc_0002ejspAddServerPrc_jsp_35._jspService(_0005cAddServerPr
c_0002ejspAddServerPrc_jsp_35.java:156)
Feb 21 16:52:45 2001: at
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:130)
Feb 21 16:52:45 2001: at
javax.servlet.http.HttpServlet.service(HttpServlet.java:853)
Feb 21 16:52:45 2001: at
org.apache.jasper.runtime.JspServlet$JspServletWrapper.service(JspServlet.ja
va:164)
Feb 21 16:52:45 2001: at
org.apache.jasper.runtime.JspServlet.serviceJspFile(JspServlet.java:256)
Feb 21 16:52:45 2001: at
org.apache.jasper.runtime.JspServlet.service(JspServlet.java:361)
Feb 21 16:52:45 2001: at
javax.servlet.http.HttpServlet.service(HttpServlet.java:853)
Feb 21 16:52:45 2001: at
com.sybase.jaguar.servlet.JagServlet.service(JagServlet.java:164)
Feb 21 16:52:45 2001: at
com.sybase.jaguar.servlet.JagRequestDispatcher.service(JagRequestDispatcher.
java:760)
Feb 21 16:52:45 2001: at
com.sybase.jaguar.servlet.ServletEngine.service(ServletEngine.java:528)
Feb 21 16:52:45 2001: at
com.sybase.jaguar.servlet.ServletServiceImpl.doService(ServletServiceImpl.ja
va:52)
Feb 21 16:52:45 2001: at
com.sybase.jaguar.servlet._sk_JaguarServlet_ServletService.invoke(_sk_Jaguar
Servlet_ServletService.java:140)
Feb 21 16:52:45 2001: SystemException: UNKNOWN
(DCSoft_ISPPro/ServerManager/vsAddServer - @127.0.0.1)
my Exception class is:
public class SMException extends java.lang.Exception
{
public SMException(int a)
{
// TODO: implement
detail=a;
}
public String toString()
{
// TODO: implement
return ("SM");
}
public int getNumber()
{
// TODO: implement
return (detail);
}
public String getMessage()
{
// TODO: implement
return ("SM" + detail);
}
private int detail;
}
in the remote interface, I have this method vsAddServer:
public EJBResult vsAddServer(String connString, String serverName, String
ipAddress, String secret, String comments) throws java.rmi.RemoteException;
and the bean implementation of this method is:
public EJBResult vsAddServer(String connString, String serverName, String
ipAddress, String secret, String comments) throws
javax.ejb.EJBException,SMException
{
// TODO: implement
Connection conn = null;
ResultSet result = null;
Statement stmt = null;
PreparedStatement pstmt = null;
EJBResult resultCode = new EJBResult();
String arrString[];
arrString = new String[1];
try
{
secret = nullTest(secret);
comments= nullTest(comments);
Class.forName("com.sybase.jdbc2.jdbc.SybDriver").newInstance();
....
....
....
....
if (result.isBeforeFirst())
{
throw new SMException(2004); I'm trying to throw this
Exception
}
if (result != null) result.close
}catch(SMException e)
{
arrString[0] = new String(e.toString());
throw new SMException(e.getNumber());
}catch(Exception e)
{
throw new javax.ejb.EJBException(e.toString());
}finally
{
try
{
if (pstmt != null) pstmt.close();
if (stmt != null) stmt.close();
if (result != null) result.close();
if (conn != null) conn.close();
}catch(Exception e)
{
throw new javax.ejb.EJBException(e.toString());
}
pstmt = null;
stmt = null;
result = null;
conn = null;
}
arrString[0]=new String("SM10000");
resultCode.setArrString(arrString);
return(resultCode);
}
I want to know how I can throw my own custom Exception from EJB method
Many Thanks if somebody can help me
Hrair Karaboyadjian
Software Engineer
DC Soft S.A.L.
Tel: +961-1-385425
Fax: +961-1-385428
P.O.Box 11-337
Beirut - Lebanon
email: mailto:[EMAIL PROTECTED]
http://www.dcsoftintl.com
Hrair Karaboyadjian
Software Engineer
DC Soft S.A.L.
Tel: +961-1-385425
Fax: +961-1-385428
P.O.Box 11-337
Beirut - Lebanon
email: mailto:[EMAIL PROTECTED]
http://www.dcsoftintl.com
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