Yes, if I wanted 12 watts (which is the same as 15 for all intents and 
purposes) I could run barefoot. However, why stress the KX3 by running it as 
hard as possible, key down, for long digital transmissions like PSK31? 

I never said there was a problem or that something was wrong. I simply am 
curious if the designers of the amp who monitor this reflector know what it 
does with less RF input than what gives an LCD indication of power. That's all.

Jim / W6JHB


> On Jun 15, 2016, at 19:15, Fred Jensen <[email protected]> wrote:
> 
> Hmmm ... I guess first question is, what's the problem?  25 W to 20W is 
> slightly less than 1 dB, 0.16 S-unit.  Just run barefoot?
> 
> The LED Power display on the KPA500 is digital.  It "measures the power," and 
> puts it into one of a number of bins.  If something is in the bin, it lights 
> the LED.  If the measured power isn't high enough for the lowest bin, all the 
> bins are empty, no LED's light up, although there is still RF being made.
> 
> Measuring power with simple instruments is hard ... well, sort of impossible. 
>  You can measure the voltage, but then you need to know the impedance, a 
> complex number, not easily measured with a DVM.  You can measure the current 
> -- same problem.  KPA500 is designed to emit 500W with 25-30W input.  I think 
> you're pushing the envelope here and nothing is wrong.
> 
> 73,
> 
> Fred K6DGW
> - Northern California Contest Club
> - CU in the Cal QSO Party 1-2 Oct 2016
> - www.cqp.org
> 
>> On 6/15/2016 4:54 PM, James Bennett wrote:
>> I share my KPA500 with a K3 and a KX3. When I want to operate JT65 or
>> JT9 I normally run about 25 watts out, using the KX3 to drive the
>> amp. With the KX3 set to 1.8 watts out, the amp gives me 25; with 2.2
>> watts from the KX3, I get 30 watts out from the amp.
>> 
>> But, what if I want to run 20 watts? Or 15? When I back the KX3 power
>> level below 1.8, the KPA500 shows zero on the LED power display. Does
>> this mean it is no longer amplifying, or is it actually amplifying
>> but not enough for the circuitry to determine how much?
>> 
>> Jim Bennett / W6JHB Folsom, CA
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