Now then, whether you want to acknowledge it or not, a ferrite core IS
a lossy dielectric and can get hot when you put a high enough RF
voltage across it INDEPENDENT OF THE CURRENT FLOWING THROUGH THE
WINDING AROUND THE CORE. You can find innumerable references to the
dielectric losses of ferrite materials if you just bother to do some
internet searching. This is NOT an insulation breakdown issue ... not
at all.
A dielectric is defined as an insulator . A ferrite core is not a
dielectric (insulator), This is the false fact in your theory.
*Dielectric heating*, also known as*electronic heating*,*radio frequency
heating*, and*high-frequency heating*, is the process in which aradio
frequency <https://en.wikipedia.org/wiki/Radio_frequency>(RF)
alternating electric field, orradio wave
<https://en.wikipedia.org/wiki/Radio_wave>ormicrowave
<https://en.wikipedia.org/wiki/Microwave>electromagnetic radiation
<https://en.wikipedia.org/wiki/Electromagnetic_radiation>heats
adielectric <https://en.wikipedia.org/wiki/Dielectric>material.
It is the dielectric material being heated via molecular rotation.
A ferrite core although not a good conductor also is not a dielectric,
and no mention of dielectric loss is attributed to its heating losses ;
https://elnamagnetics.com/wp-content/uploads/library/TSC-Ferrite-International/Predicting_Temperature_Rise_of_Ferrite_Cored_Transformers.pdf
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