If you weren't too stubborn you could find many, many online references to the dielectric characteristics of ferrites.  A ferite core absolutely IS a dielectric.  There is nothing false about what I've been telling you.

Dave  AB7E



On 9/2/2020 9:02 PM, Adrian wrote:


Now then, whether you want to acknowledge it or not, a ferrite core IS a lossy dielectric and can get hot when you put a high enough RF voltage across it INDEPENDENT OF THE CURRENT FLOWING THROUGH THE WINDING AROUND THE CORE.  You can find innumerable references to the dielectric losses of ferrite materials if you just bother to do some internet searching.  This is NOT an insulation breakdown issue ... not at all.

A dielectric is defined as an insulator . A ferrite core is not a dielectric (insulator),  This is the false fact in your theory.

*Dielectric heating*, also known as*electronic heating*,*radio frequency heating*, and*high-frequency heating*, is the process in which aradio frequency <https://en.wikipedia.org/wiki/Radio_frequency>(RF) alternating electric field, orradio wave <https://en.wikipedia.org/wiki/Radio_wave>ormicrowave <https://en.wikipedia.org/wiki/Microwave>electromagnetic radiation <https://en.wikipedia.org/wiki/Electromagnetic_radiation>heats adielectric <https://en.wikipedia.org/wiki/Dielectric>material.

It is the dielectric material being heated via molecular rotation.


A ferrite core although not a good conductor also is not a dielectric, and no mention of dielectric loss is attributed to its heating losses ;


https://elnamagnetics.com/wp-content/uploads/library/TSC-Ferrite-International/Predicting_Temperature_Rise_of_Ferrite_Cored_Transformers.pdf

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