Hello,
Is this Ranked Pairs tie-breaking method usable?:
"Suppose A>B and C>D are of equal strength as strength is being defined.
If B is not D and one of B and D defeats the other pairwise, then rank
A>B ahead of C>D if D defeats B, or vice versa if B defeats D.
Else (when B is D, or B and D tie pairwise) rank A>B ahead of C>D if A
defeats C pairwise, and C>D ahead of A>B if C defeats A pairwise."
Maybe this or something like it is already someone's version. MAM uses
Random Ballot by this stage, and Eric Gorr's "Deterministic #1" says that
"[equivalent] defeats are considered together with previously kept defeats,"
which sounds to me like an equivalent defeat could be discarded even if
it doesn't contradict anything.
Any other approaches?
Kevin Venzke
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