Mr. Schulze wrote in part (Date: Wed, Jun 10, 1998 1:18 PM EDT)-- Tideman's method fails to meet Fishburn's "No-Show Criterion". *** Example 1: 37 voters vote C > A > B > D. 20 voters vote B > D > A > C. 18 voters vote A > D > C > B. 15 voters vote B > D > C > A. 07 voters vote D > A > C > B. 03 voters vote C > B > A > D. *** Thus: Candidate C wins the election. Example 2: Suppose, that additional 6 voters vote B > D > C > A. Then, we have: 37 voters vote C > A > B > D. 20 voters vote B > D > A > C. 18 voters vote A > D > C > B. 21 voters vote B > D > C > A. 07 voters vote D > A > C > B. 03 voters vote C > B > A > D. *** Thus: Candidate A wins the election. *** ----------- D- I note the first and second choices and the totals --- (100 voters- 51 majority) A 18 44 62 Should A win ? B 35 03 38 C 40 00 40 D 07 53 60 (106 voters- 54 majority) A 18 44 62 B 41 03 44 C 40 00 40 D 07 59 66 Should D win ?
