Yet another Condorcet circular tie--
48 AC
1 AB
48 B
1 CA
1 CB
50 A > 49 B
50 B > 49 C
50 C > 49 A
Does common sense say which candidate (and his/her voters) should lose to
resolve the tie ?
C should lose and his/her 2 first choice supporters. The reason- the lowest
number (i.e. smallest minority) of voters should have to drop their first
choices to resolve the tie.
Thus A should win.
The circular tie breaker applies in like manner with 4 or more candidates in
the circular tie and then redoing the head to head math.
