Once again-- All sorts of mysteries arise when choice C appears in addition to A and B
Original N1 A > B N2 B > A N Total N1.1 C > A > B N1.2 A > C > B N1.3 A > B > C N1 subtotal N2.1 C > B > A N2.2 B > C > A N2.3 B > A > C N2 subtotal N Total Thus---- C may beat both (be a Condorcet winner), lose to both (be a Condorcet loser) or beat A or B (be a Condorcet survivor). C may cause A or B or be a 100 percent clone of C (cloner) or be a 100 percent clone of A or B (clonee). A number of methods try to make a big deal that such- and- such case may happen if choice Z is added, removed or is a cloner or a clonee. Add choice D for more math -- 4 x 3 x 2 x 1 = 24 combinations. Add 100 to 0 percentage *absolute* votes to the math for more complexity.
