On Fri, 21 Feb 2003, Steve Barney wrote: > Forest: > > How do you decompose my example (from my last email, #10873), and what do you > get?: > > 3:A>B>C > 5:A>C>B > 0:C>A>B > 5:C>B>A > 0:B>C>A > 5:B>A>C
Subtract out five copies of the cycle ACB+CBA+BAC. That leaves 3*ABC. Forest ---- For more information about this list (subscribe, unsubscribe, FAQ, etc), please see http://www.eskimo.com/~robla/em
