Great ideas in a much neglected area!
 
A couple of comments:
 
1.  It seems to me that it is better to start by eliminating the pairwise loser 
of the least (as opposed to most) correlated pair of candidates.  This reduces 
burial incentive.
 
2.  These kinds of methods tend to lack monotonicity because increasing support 
for a winner can change the correlations in such a way that the winner faces an 
unfavorable pairwise contest that didn't materialized before.
 
3.  To overcome the monotonicity problem, the correlation data could be 
obtained separately from the rankings.  However, this tends to open up 
opportunities for manipulations of the correlations, since they are not tied to 
the rankings.
 
Taking into account (1), (2) and (3) I've come up with the following idea, 
which I call "Narrowing In:"
 
(A)  Have the candidates fill out extensive questionnaires with a wide variety 
of questions related to a wide variety of issues.
 
(B)  Publish their responses, as well as the correlations between the 
candidates based on their responses.
 
(C)  Have the voters rank the candidates.
 
(D)  While there remain two or more candidates, eliminate the pairwise loser of 
the least correlated pair.
 
Remarks:
 
Note that if issue space turns out to be essentially one dimensional, the 
method starts eliminating candidates from the outside, narrowing in on the 
Condorcet winner.
 
Because the candidates' responses to the questionnaire are published before the 
vote, they have no (unusual) incentive to lie about their position on the 
issues.
 
This method is monotone.  It has little incentive for favorite betrayal since 
Favorite and Compromise tend to be highly correlated, so the decision between 
them tends to come late in the game, if at all. 
 
 In fact, the only time there could be a favorite betrayal incentive is if 
Compromise and Favorite formed the least correlated pair, while there still 
remained at least one other candidate to be eliminated.  
 
Even then there would be no betrayal incentive if the pairwise winner of the 
pair had has great a chance against the other remaining candidate(s) as the 
pairwise loser of the pair.
 
What do you think?
 
Forest

<<winmail.dat>>

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