I said "Maybe from 0 to 1 it's an improper integral that evaluates to 1/e."

I meant:

Maybe, from 0 to R, it's an improper integral such that that when sit's 
olved and added to the integral from R to 1, and when the result is set 
equal to 0, and the resulting equation solved fo R, the result for R is 1/e.

Mike Ossipoff


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