Joe-- You asked what is the role of 1/e in the formula for Bias-Free's round-off point. I tried to answer by saying that ((b^b)/(a^a))(1/e) is just the result I got when looking for the round-off point that would make cycles' s/q = 1. That's all I can say about where the formula came from.
What was the meanng of your question? In what sense was "role" intended? Unless I made an error (and I probably didn't make an error), the formula for Weighted Bias-Free doesn't contain "e". Weighted Bias-Free is gotten by a/q-1 and b/q-1 by a weight that approximates the frequency density of states at a particular q value. I approximate that density function by: B/(q+A), which has the same general behavior as the distribution function, though of course it will be a rough approximation. Mike Ossipoff ---- election-methods mailing list - see http://electorama.com/em for list info
