Using a frequency distribution function, F(q), of B*exp(-A*q), write an expression for the number of seats possessed by states in the cycle between consecutive integers a and b. And write an expression for the number of quotas possessed by states between in the cycle between a and b. Set those two expressions equal and solve for R, the rounding point in that cycle.
I call it Weighted Webster because, using a uniform frequency distribution, Webster can be arrived at in that way. I now propose four methods: Cycle-Webster Adjusted-Rounding Weighted-Webster Webster Mike Ossipoff ---- election-methods mailing list - see http://electorama.com/em for list info
