Dear Forest, nice idea, but I'm almost sure it will not be cloneproof. Consider three options x,y,z. Then the circuit resistance from x to z is 1 / (1/Rxz + 1/(Rxy+Ryz)). When we add a y-clone y', it seems we get 1 / (1/Rxz + 1/(Rxy+Ryz) + 1/(Rxy'+Ry'z)) which is smaller. Although all other pairwise circuit resistances will also decrease, it seems that this will not happen in such a coordinated way that the winner is preserved.
Yours, Jobst > Has anybody explored this idea? > > Make an electrical circuit with a terminal for each candidate. > > For each pair of terminals attach a diode that has a different > resistance in each direction: the resistance in the direction from > candidate i to candidate j is proportional to the number of ballots > on which candidate j is ranked above candidate i. > > After all of the diodes are attached measure the circuit resistance > between terminals i and j. > > The candidate X against whom the maximal resistance is minimal is the > winner. > > Forest > ---- > election-methods mailing list - see http://electorama.com/em for list > info
pgplSH7wG3qxw.pgp
Description: PGP signature
---- election-methods mailing list - see http://electorama.com/em for list info
