As far as I can understand, diferent places tell us about the Schulze-method like:
1. A candidate "path-beats" another one, if its best beatpath to the other is the better. The Schulze-winners are the "un-path-beaten" ones. or, which gives the same result: 2. Calculate the Schwartz set, drop the outsiders. Then drop the weakest defeat. Do this while possible, and the remainders are the Schulze-winners. I think maybe we should add an instruction: If there are more than one Schulze-winners, do the whole thing again with only them. Example: ABCD BCDA BACD CDAB DACB Here A beats B and C, B beats C and D, D beats A. These are all 3:2 beats. And C beats D by 4:1. Since A > B > C > D > A there are beat-paths from each one to each other one. And only C > D is stronger, all other ones are the same. So A, B, C are all "un-path-beaten", or, if you like it, in the first step, A,B,C,D are all in the Schwartz set, then dropping all weak defeats, only C > D defeat remains. So, A, B, C are the Schulze-winners. But A can rightfully say that itself alone must be declared as a winner, because it is a Condorcet winner among A, B, C. It is a very unlikely scenario, I admit. Peter Barath ____________________________________________________________________ Tavaszig, most minden féláron! ADSL Internet már 1 745 Ft/hó -tól. Keresse ajánlatunkat a http://www.freestart.hu oldalon! ---- election-methods mailing list - see http://electorama.com/em for list info
