On Wed, Sep 24, 2008 at 03:37:53PM +0100, Nicholas Cole wrote:
> E = email.mime.multipart.MIMEMultipart()
> print E.as_string()
>
> Then E is given a "MIME-Version: 1.0" header, which I don't think it
> should have (the "parent" email message will have that header, of
> course).
>
> I have a feeling, therefore, that I am doing something wrong! Should
> I not be using the MIMEMultipart() calss for this purpose? And if not,
> what should I be using?
MIMEMultipart is a class for the top-level part (the entire message).
For subparts use classes like MIMEText et al. Compare these 3 examples:
----- 1 -----
from email import MIMEText
msg = MIMEText.MIMEText("This is a simple message", _charset="latin-1")
msg["Subject"] = "Text"
print str(msg)
----- /1 -----
----- 2 -----
from email import MIMENonMultipart
msg = MIMENonMultipart.MIMENonMultipart("text", "plain", charset="latin-1")
msg["Subject"] = "Simple"
msg.set_payload("This is a simple message")
print str(msg)
----- /2 -----
----- 3 -----
from email import MIMEMultipart, MIMEText
msg = MIMEMultipart.MIMEMultipart()
msg["Subject"] = "Multipart"
part = MIMEText.MIMEText("This is a subpart", _charset="latin-1")
part["Subject"] = "Subpart"
msg.attach(part)
print str(msg)
----- /3 -----
Oleg.
--
Oleg Broytmann http://phd.pp.ru/ [EMAIL PROTECTED]
Programmers don't die, they just GOSUB without RETURN.
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