On Wed, Sep 24, 2008 at 4:06 PM, Oleg Broytmann <[EMAIL PROTECTED]> wrote:
> On Wed, Sep 24, 2008 at 03:37:53PM +0100, Nicholas Cole wrote:
>> E = email.mime.multipart.MIMEMultipart()
>> print E.as_string()
>>
>> Then E is given a "MIME-Version: 1.0" header, which I don't think it
>> should have (the "parent" email message will have that header, of
>> course).
>>
>> I have a feeling, therefore, that I am doing something wrong! Should
>> I not be using the MIMEMultipart() calss for this purpose? And if not,
>> what should I be using?
>
> MIMEMultipart is a class for the top-level part (the entire message).
> For subparts use classes like MIMEText et al. Compare these 3 examples:
>
> ----- 3 -----
> from email import MIMEMultipart, MIMEText
> msg = MIMEMultipart.MIMEMultipart()
> msg["Subject"] = "Multipart"
>
> part = MIMEText.MIMEText("This is a subpart", _charset="latin-1")
> part["Subject"] = "Subpart"
>
> msg.attach(part)
> print str(msg)
> ----- /3 -----
>
> Oleg.
Dear Oleg,
Thanks for the examples - things are looking clearer. However, in
version 3, on my system the subpart is still given a MIME-Version
header. Is this not incorrect?
Also, according to the documentation "A MIME-Version: header will also
be added" to the MIMEMultipart class, even though it actually seems to
be added by the MIMEBase class, and therefore to all subclasses.
Best wishes,
Nicholas
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