John, Let's see. hmmm.... 120Vac, 27A @ 90 degree phase angle (PA) and R approx 3 ohms. Actually it sounds as if you're mixing apples and oranges and getting fruit cocktail. If I remember my basic circuits classes many, many years ago (clear those cobwebs out), R always attributes to 0 degrees PA, therefore, I would have to say that the 90 degrees PA you're expereincing is solely attributed to inductance, At 90 degrees PA, the pure resistance of the wiring should have a negligible effect. Therefore, what you should be looking for is impedance, or inductive reactance, either in place of the dc wiring resistance or in addition to it. Once you've considered this, the calculated results you get may be more in line with your measured results. Just some humble opinions full of cobwebs. Good luck. Best regards, Ron Pickard [email protected]
______________________________ Reply Separator _________________________________ Subject: Inrush current and utility power line reistance Author: <[email protected]> at INTERNET List-Post: [email protected] Date: 9/11/98 11:02 AM From: John Garrett@HNS on 09/11/98 11:02 AM To: ieee pstc list <[email protected]> cc: Subject: Inrush current and utility power line reistance Hello All, I have a question with respect to the typical resistance of the mains utility wiring; from the mains utility transformer into a residential or industrial building. But first a little history on the problem: When testing a 30 W power supply at 120VAC, the inrush current at a phase angle of 90 degrees measured 27A peak (4 unique sites were tested). Calculating inrush current is a fairly straight forward application of ohms law: Inrush Current = peak voltage divided by the dc resistance ( I = Vpeak / R) (where R is the series resistance from the power line into the p/s through the EMI filter through the rectifier and the bulk capacitor back out the other leg of the line) In this application the result of the above equation is I = (120 VAC*1.414) / 3.00 ohms or I = 56.6 Amps... where 3 ohms is the worst case resistance internal to the power supply (The assumption here being there is little if any resistance external to the power supply that will add significantly to this internal resistance). The problem is this: the calculated number (56.6 A) does not come close to the measured (27A). If fact, when we look at the measured data it appears as if the external resistance, i.e. the resistance of residential or industrial wiring from the utility mains transformer to the building and internal to the building, is adding a very significant amount of resistance (approx. 3.0 ohms). This is very hard to believe! But it is repeatable. We are checking these measurements even as I write, but my questions are simple. First, am I missing something here with respect to second order effects? Second, does anyone have a feel for the resistance of the power lines from the utility mains xfmr to the service entrance and into a residential or industrial building? Have any studies been performed that I can refer to for this type of information? Any help would be greatly appreciated. John Garrett Principal Engineer Hughes Network Systems Phone (301) 601-2699 11717 Exploration Lane FAX (301) 428-2835 Germantown, MD 20876 Email: [email protected] --------- This message is coming from the emc-pstc discussion list. To cancel your subscription, send mail to [email protected] with the single line: "unsubscribe emc-pstc" (without the quotes). For help, send mail to [email protected], [email protected], or [email protected] (the list administrators). --------- This message is coming from the emc-pstc discussion list. To cancel your subscription, send mail to [email protected] with the single line: "unsubscribe emc-pstc" (without the quotes). For help, send mail to [email protected], [email protected], or [email protected] (the list administrators).
