Is there a "permeability" or "permitivity" quantity given to these solids, 
in order to calculate the loss at a given frequency?  Since the solid's 
electrical conductivity has no effect on its ability to pass or reflect EM 
energy in the visible light spectrum, then you would conclude that there 
are no issues of capacitance and inductance.

Anyone know what the formulas are to calculate this quantity, and what 
given variables are required to do so?  At what frequency does EM radiation 
stop acting like electric wave propagation and start behaving like Light?

This seems like a very interesting topic, and one that many of us EMC 
engineers (maybe not the good ones, but the rest of us) are in the dark 
about.  (pun intended.)

Regards,


Randy Flinders
EMC Engineer
Emulex Network Systems
[email protected]
(714) 513-8012

----------
From:   [email protected]
Sent:   Thursday, March 11, 1999 2:02 PM
To:     "smtp@WILTRON7@Servers[\"Allen Tudor\" <[email protected]
Cc:     [email protected]
Subject:        re: Visible Light & EMC

Allen,

You are right. Transparent solids have much less loss for light waves than
opaque. And mirror-like solids reflect most of light waves.

B Ma

-------------
Original Text
From: "Allen Tudor" <[email protected]>, on 3/11/99 1:21 PM:
This question sounds goofy, but here goes anyway....

Why doesn't visible light travel through solid objects (plastic, wood,
etc)?  Unless I've totally missed the boat, visible light is
electromagnetic energy beginning at about 100,000GHz.  So why doesn't it
behave like electromagnetic energy in the radio spectrum?  My guess is that 
it has something to do with the wavelength vs. the thickness of the object.



Allen Tudor, Compliance Engineer
PairGain Technologies                  tel:  (919)875-3382
2431-153 Spring Forest Rd.           fax: (919)876-1817
Raleigh, NC  27615                           email:
[email protected]



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