Part 15.231 devices use a duty cycle correction factor to adjust peak readings. The duty cycle represents the fractional on-time over a given period of time (that must be under some limit). Anyways, given this fractional time, d, how do you make the conversion to dB?
10log(d) or 20log(d)? There have been some misinterpretations, since the readings are made at a span of zero hertz (voltage readings). Normally, a reduction in voltage would use the 20log scale. However, since the duty cycle does not represent a scale down (it represents the off-time versus on-time), the 10log scale seems more appropriate. I have seen conflicting documents, so would like your professional opinions! Thanks, Stuart Lopata ------------------------------------------- This message is from the IEEE EMC Society Product Safety Technical Committee emc-pstc discussion list. Visit our web site at: http://www.ewh.ieee.org/soc/emcs/pstc/ To cancel your subscription, send mail to: [email protected] with the single line: unsubscribe emc-pstc For help, send mail to the list administrators: Michael Garretson: [email protected] Dave Heald [email protected] For policy questions, send mail to: Richard Nute: [email protected] Jim Bacher: [email protected] All emc-pstc postings are archived and searchable on the web at: No longer online until our new server is brought online and the old messages are imported into the new server.
