I think Don is right: the resistive load measurement is not useful; yo need
to measure the e.m.f. and to perform two reactive load measurements in
order to solve the equations.
-------------------------------------------------------------
ESAOTE S.p.A. Paolo Peruzzi
Research & Product Development Design Quality Control
Via di Caciolle,15 tel:+39.055.4229306
I- 50127 Florence fax:+39.055.4223305
e-mail: [email protected]
I read in !emc-pstc that [email protected] wrote (in
<[email protected]>) about 'Measuring
AC Line Impedance' on Tue, 5 Nov 2002:
>Part 1. This measurement will NOT give just the resistive part of the
>source impedance.
Your post is so long that it is not clear what you are trying to
correct. Also, by top-posting you make it more difficult to understand
how your comments relate to previous texts.
If we measure the voltage developed across a resistive load, we have one
equation with three unknowns, e.m.f., source inductance and source
resistance. If we measure the voltage developed across a pure capacitive
load (or one with known losses), we also have one equation with three
unknowns. If we measure the *open-circuit* voltage, we immediately have
the value of one unknown, the e.m.f. or Thevenin equivalent source
voltage. That leaves us with two equations and two unknowns, which are
soluble.
--
Regards, John Woodgate, OOO - Own Opinions Only.
http://www.jmwa.demon.co.uk
Interested in professional sound reinforcement and distribution? Then go to
http://www.isce.org.uk
PLEASE do NOT copy news posts to me by E-MAIL!
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