George,
 
this formula is valid only for free space propagation but it is correct for
all frequencies. The 20LOG(Freq) part takes care of the fact that the capture
area of the receiver antenna decreases as 20LOGF. As you know, there is not
really a difference in path loss as frequency is increased. That is, if I
transmit a signal at two different frequencies and both have the same E-field
amplitude at point A, they will both have the same E-field amplitude at point
B, along the path of propagation.
 
Here is a link to a program that claims to solve for surface wave propagation
at MF and HF:
 
http://www.btinternet.com/~g4fgq.regp/
 
You want to find GRNDWAV3
 
Another way to explore surface wave path loss is to use NEC (I use NEC-2) and
set up the appropriate antennas at each end of the path. Apply power to one
and measure the current (power) in the other. It will solve for a flat path of
course and doesn't take the curvature of the earth, or obstacles into account.
Also, I am told that the far-field ground modeling of NEC-2 is not the same as
for near-field and so it isn't true-to-life. However, it might be a good way
to explore different antennas and ground types to get a feel for the issues. 
 
       Dave Cuthbert
       Micron Technology
 
 

From: [email protected] 
mailto:[email protected]] On Behalf Of George Stults
Sent: Thursday, December 02, 2004 11:48 AM
To: [email protected]
Subject: path attenuation in AM band



Hi Folks,

 

I have an equation for the attenuation of a radiated signal as a function of
(distance, frequency, and environment.)  

 

ATTN = 37 + 20 Log (Freq)  + 20 Log (Dist),  Freq is in MHz, Distance in
Miles, Environment is free-space/line-of-sight (N=2).

 

My information is that this equation works well for 2.4GHz frequency range.   

 

Could anyone tell me whether this equation would still make valid predictions
for attenuation in the AM band. (535 – 1650)Khz, and lower?  

 

Or could anyone suggest an equation that would predict path loss as a function
of distance, frequency, and environment for lower frequencies?

 

Thanks in advance.

 

George Stults

 

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