This kind of heating specifically relies on eddy current induction.  A
solenoidally wound coil is placed around the cylindrical work-piece, which is
concentric with the induction coil.  If you work out the vectors, the eddy
currents circulate around the circumference of the work-piece, heating it. 
I'm guessing one reason for using such a high frequency as opposed to a more
typical 150 kHz is skin depth.  With a much smaller skin depth, the eddy
currents flow closer to the surface.  The increased current density increases
the resistive heating effect.



From: "Price, Ed" <[email protected]>
List-Post: [email protected]
Date: Thu, 15 Sep 2005 16:41:12 -0700
To: [email protected]
Cc: [email protected]
Subject: RE: When is a cable shield not a cable shield?





The principle is demonstrated by industrial induction heaters, where a few
seconds of 13 MHz eddy current loss will turn the end of an auto engine valve
cherry red. 

Ed Price 
[email protected]                   WB6WSN 
NARTE Certified EMC Engineer & Technician 
Electromagnetic Compatibility Lab 
Cubic Defense Applications 
San Diego, CA USA 
858-505-2780 (Voice) 
858-505-1583 (Fax) 
Military & Avionics EMC Is Our Specialty 



> -----Original Message----- 
> From: Robert A. Macy [mailto:[email protected]] 
> Sent: Thursday, September 15, 2005 3:28 PM 
> To: Ken Javor 
> Cc: [email protected] 
> Subject: Re: When is a cable shield not a cable shield? 
> 
> Eddy currents exist everywhere the conductor looks like a 
> shorted turn on a transformer.  
> 
> Imagine a perfectly balanced pair of wires, driven in a 
> perfetly balanced manner. A wire down, a wire back - a loop.  
> That pair will radiate right out through its loop. 
>  A simple plate of conductor placed over the loop will get 
> eddy currents generated in it that "cancels" to lower radiation.  
> 
> The plate does not have to be terminated to have this effect. 
>  Simply covering the surface of the loop is sufficient.  Plus 
> with the wires perfectly balanced and the drive pervectly 
> balanced there will be no residual signal put upon the plate, 
> so the plate does not radiate, or reradiate.  
> 
>                       - Robert - - 2005 IEEE Symposium on Product Safety
Engineering 3-4 October   Schaumburg, IL http://www.ieee-pses.org/symposium 

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- 2005 IEEE Symposium on Product Safety Engineering 3-4 October Schaumburg, IL
http://www.ieee-pses.org/symposium 

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